3x^2+100x+35000=36300

Solution for 3x^2+100x+35000=36300 equation:

3x^2+100x+35000=36300

We move all terms to the left:

3x^2+100x+35000-(36300)=0

We add all the numbers together, and all the variables

3x^2+100x-1300=0

a = 3; b = 100; c = -1300;
Δ = b2-4ac
Δ = 1002-4·3·(-1300)
Δ = 25600
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:
$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}$
$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}$

$\sqrt{\Delta}=\sqrt{25600}=160$
$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(100)-160}{2*3}=\frac{-260}{6}
=-43+1/3
$
$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(100)+160}{2*3}=\frac{60}{6}
=10
$